ISO C++ forbids taking the address of a bound member function to form a point

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调试中遇见这个报错信息，
ISO C++ forbids taking the address of a bound member function to form a pointer to member function. Say '&ZButton::OnKeyPress'

实际代码如下，
ZEvent_t ZButton::OnKeyPress( FEICmd_Key_t key )
{
if( key == ZSERVER_SELECT_KEY )
{
return (ZEvent_t)EVENT_BN_CLICKED ;
}
return EVENT_UNKNOWN_MESSAGE;
}

FEI_ON_KEYPRESS_MESSAGE( OnKeyPress )

#define FEI_ON_KEYPRESS_MESSAGE(memberFxn)\
{MESSAGE_REMOTE_FRONT_KEYBOARD, MSG_KEYPRESS, ANY_INSID, (ZEvent_t)EVENT_UNKNOWN_MESSAGE, (FEI_PMSG)&memberFxn},


怎么解决？
Because the syntax of C++. The expression &T::f is a pointer to member. No other syntax will do, not T::f or &(T::f) or just plain f.

所以，我修改如下：
FEI_ON_KEYPRESS_MESSAGE(&ZButton::OnKeyPress )
#define FEI_ON_KEYPRESS_MESSAGE(memberFxn)\
{MESSAGE_REMOTE_FRONT_KEYBOARD, MSG_KEYPRESS, ANY_INSID, (ZEvent_t)EVENT_UNKNOWN_MESSAGE, (FEI_PMSG)memberFxn},
好了。